speed. No, because gas does not behave like an ideal gas if $T>T_{B}$ and $T Physics > Molecular Physics | Thermodynamics. MCQs on Physics Thermodynamics : 1. Work is a path function. Second law of thermodynamics. Why it is unique ? Zeroth law of thermodynamics. SHOW SOLUTION $\frac{1}{2} m c^{2}=0$ since $\frac{1}{2} m \neq 0 \quad \therefore c=0$. 1.3. The increaments in the temperature on kelvin scale are the same as the those of the celsius scale. Find all the information you need to solve common problems in thermodynamics, the realm of physics relating to energy in the form of heat. How is the molar gas constant related to the principal gas constant? Establish the relation between two principal specific heats of a gas on the basis of this law. SHOW SOLUTION Part 1 Problem 1. As a matter of fact, a total of 45 questions will be asked from Physics. Download eSaral App for Video Lectures, Complete Revision, Study Material and much more...Sol. On the root mean square speed of the molecules? First law of thermodynamics. Thus, the absolute zero is that temperature at which the r.m.s. $P_{\gamma} v^{\gamma-1} . At what temperature does all molecular motions cease? Where $m=$ Mass of one molecule, $N=$ Number of molecules present in volume $V$ and$\bar{c}^{2}=$ Meansquare velocity If $V$ is the volume of $1 g m$ molecule $(1$ mole) of a gas. $\therefore \frac{d P}{d V}=-\frac{\gamma P V^{\gamma-1}}{V^{\gamma}}=-\frac{\gamma P}{V}$ The gas equation is, $P V^{\gamma}=$ constant, After a short time interval, the gas returns to equilibrium states which lies on its P-V-T surface. The final temperature can be the mean temperature of $\left(\frac{T_{1}+T_{2}}{2}\right)$ only. Thus, the absolute temperature of a gas is directly proportional to the mean square velocity of the molecules of a gas. Also get to know about the strategies to Crack Exam in limited time period. 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